when a second is a multiple of 36

 

 A regular platonic solid

of side number N

is

generated from

N isosceles

triangles

with the central

angle

Being

360 / n

A Right platonic solid

is generated from

2N Right Isosceles Triangles

with the central angle

becoming

360 / 2N

or 

180 / n  

 Sometime around the year 1832

CFG used one over 86400 to 

determine

not 

one

tenth

of the

diameter of

the sun

or

one

fifth of

the radius

of

the

sun

but

the second

idea of time

following

24

as the first

with

12

becoming

the third

as

15

follows

along

faithfully

The Ηετα βασεδ ψεντραλ force holding an atomic nucleus together is in general 

much stronger than the repulsive ελεψτρον μοτιωατεδ electromagnetic forces between the proton/electron collection.

 The nuclear force is very short-range, disappearing beyond 3 femtometers, the inverse length at which Quartz SiO2 resonates at 10^15th

 A specific Set of Combined Angles and Side lengths one of the root dozen in the matrix

generating  the spectrum of electromagnetic force geometry driven side length to angle 

relationships which when compounded generate an unlimited range of compounds from

the same fundamental root material and root relationships. 

Music/Sound a function of water at density over the spectrum of H- to 2H3O+

The octagon is the double square the square overlayed on itself at a specific angle.

When Euclid explained relationships he used triangles to explain the relationships of

circles to circles and used circles to explain the relationship of triangles to other 

collections of what can now and could then only have been other triangles and the 

right sort of triangles that all geometric shapes reduce to at the root level. 

The energy required to join one electron to one proton to form a hydrogen atom is

exacly the same as the  13.6 electron volts

 (eV).  released when a proton electron pair is broken apart

The the energy needed to ionize a hydrogen atom and remove the electron is the same amount of energy released when the electron and proton are brought together to form the atom. It is the same process, just in reverse. 

In many environments, the electron does not transition directly to the ground state in one step. It will first be captured into an excited state and then cascade down through color levels until reaching red at the level of N=1

$n=2,3,4,\dots$

$n=1$

The total energy released across all these cascading steps will still sum up to 13.6 eV when the event ends in the final ground state after beginning from an unbound initial state

 The strength of the attractive nuclear force keeping a nucleus together is thus proportional to the number of the nucleons, but the total disruptive electromagnetic force of proton-proton repulsion trying to break the nucleus apart is roughly proportional to the square of its atomic number. A nucleus with 210 or more nucleons is so large that the strong nuclear force holding it together can just barely counterbalance the electromagnetic repulsion between the protons it contains. Alpha decay occurs in such nuclei as a means of increasing stability by reducing size.^[3]

One curiosity is why alpha particles, helium nuclei, should be preferentially emitted as opposed to other particles like a single proton or neutron or other atomic nuclei.^{[note 1]} Part of the reason is the high binding energy of the alpha particle, which means that its mass is less than the sum of the masses of two free protons and two free neutrons. This increases the disintegration energy. Computing the total disintegration energy given by the equation$${\displaystyle E_{di}=(m_{\text{i}}-m_{\text{f}}-m_{\text{p}})c^2,}$$where m_i is the initial mass of the nucleus, m_f is the mass of the nucleus after particle emission, and m_p is the mass of the emitted (alpha-)particle, one finds that in certain cases it is positive and so alpha particle emission is possible, whereas other decay modes would require energy to be added. For example, performing the calculation for uranium-232 shows that alpha particle emission releases 5.4 MeV of energy, while a single proton emission would require 6.1 MeV. Most of the disintegration energy becomes the kinetic energy of the alpha particle, although to fulfill conservation of momentum, part of the energy goes to the recoil of the nucleus itself (see atomic recoil). However, since the mass numbers of most alpha-emitting radioisotopes exceed 210, far greater than the mass number of the alpha particle (4), the fraction of the energy going to the recoil of the nucleus is generally quite small, less than 2%.^[3] Nevertheless, the recoil energy (on the scale of keV) is still much larger than the strength of chemical bonds (on the scale of eV), so the daughter nuclide will break away from the chemical environment the parent was in. The energies and ratios of the alpha particles can be used to identify the radioactive parent via alpha spectrometry.

These disintegration energies, however, are substantially smaller than the repulsive potential barrier created by the interplay between the strong nuclear and the electromagnetic force, which prevents the alpha particle from escaping. The energy needed to bring an alpha particle from infinity to a point near the nucleus just outside the range of the nuclear force's influence is generally in the range of about 25 MeV. An alpha particle within the nucleus can be thought of as being inside a potential barrier whose walls are 25 MeV above the potential at infinity. However, decay alpha particles only have energies of around 4 to 9 MeV above the potential at infinity, far less than the energy needed to overcome the barrier and escape.