33 or 33000
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The self replicating real relationship
ships run on it
30 60 90
root double square
Point Line Area
The root of all volume
at the cube
The
form reforms itself
using the same rules
at
scale
autoprotolysis in action
30 the B note noted
in the round
related to one
representing one
representing X
60 the Composition of 30 at the
double rate
The compression of 30 into the length
represented by the sides of every
right triangle
as found in the square root of three
related to all forms
Pump up the volume
tone it down to
the ground
the angle
adjusts
itself
as
in
the
indicated
instructions
which indicate
when an angle is
an angle and when an
angle is a line defining an
arc from a point to sets of points
all pointing at
the same
thing
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Step 1: Obtain the Volume of Earth's Oceans The total volume of Earth's oceans is
approximately 320.3 million\ cubic\ miles
This can be expressed as 320.3 times 10^6 mi^3
Step 2: Convert the Volume to Cubic Feet Since \(1\text{\ mile}=5280\text{\ feet}\), the conversion factor for cubic miles to cubic feet is \((5280\text{\ ft}/\text{mi})^{3}\). The volume in cubic feet is calculated as: \(V_{\text{oceans}}=320.3\times 10^{6}\text{\ mi}^{3}\times (5280\text{\ ft}/\text{mi})^{3}=320.3\times 10^{6}\times 5280^{3}\text{\ ft}^{3}\approx 4.70\times 10^{19}\text{\ ft}^{3}\).
Step 3: Calculate the Area of the Imaginary Flat Surface The imaginary flat surface has a radius of \(4000\text{\ miles}\). This radius is converted to feet: \(R_{\text{surface}}=4000\text{\ mi}\times 5280\text{\ ft}/\text{mi}=21,120,000\text{\ ft}\). The area of this circular surface is calculated using the formula for the area of a circle, \(A=\pi r^{2}\): \(A_{\text{surface}}=\pi \times (21,120,000\text{\ ft})^{2}\approx 1.40\times 10^{15}\text{\ ft}^{2}\).
Step 4: Determine the Height of the Water Layer When the ocean volume is evenly distributed over this surface, it forms a cylindrical layer. The height of this layer, which represents the additional radius, is found by dividing the volume by the area: = 4.70\times 10^19 ft^3 1.40\times 10^15 ft^2
approx 33,571 feet of water or 6.3 miles of water above the current surface which means
that there are approximately 500 to 1000 layers of water at different densities representing
the atmosphere each approximately 33 feet deep which is the distance at which water loses
contact with other contained organizations of water and dissociates into electrons and protons
moving charge into the air causing motion via the autoprotolysis re organizing self identified
bodies of captured volume as water and electric current follow the 30 60 90 rule of 1 : square
root of 3 : 2 also known as 1 :3 :4 where the relationship between angles identifying radiant determined points on the circumference of the circle as tangential ideas of inverted triangles centered around
the circular point of the center identifying at the required rate the required number of formal forms
which form all form found formed around points and lines in all planes in all dimensions of which
there are three and two ways to see each from the perspective of the other the same in an orthogonal
arrangement.
Final Answer The imaginary flat surface would be covered with approximately 33,571 feet of additional radius filled water.
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